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中一數學練習 ...(快!!4題)
發問:
1.) A man drove his car at 55km/h and increased his speed to 60km.h. He drove 340 km in 6 hours. How long did he drive at the higher speed?2.) The cost of 27 ball pens is &111. Among them, some cost $5 each and the remaining cost $3 each. What is the number of ball pens which cost $3 each?3.) The price of a... 顯示更多 1.) A man drove his car at 55km/h and increased his speed to 60km.h. He drove 340 km in 6 hours. How long did he drive at the higher speed? 2.) The cost of 27 ball pens is &111. Among them, some cost $5 each and the remaining cost $3 each. What is the number of ball pens which cost $3 each? 3.) The price of a pack of chocolates increases by $0.5. Now it costs $1 more to buy 14 packs of chocolates thean to buy 16 packs of chocolates before the increases. Find the original price of a pack of chocolates? 4.) There are 3 types of band show tickets: $160,$220 and $30. The number of $220 tickets sold is 120 more than that of $160 tickets. The number of $160 tickets sold is 2 times that of $320 tickets. If the total income from the tickets is $132240. Find the number of each type of tickets sold? 更新: 列式+過程+答案
最佳解答:
1. Let the man drove his car at the higher speed i.e. 60km/h for x hours: 55(6 - x) + 60x = 340 330 - 55x + 60x = 340 5x = 10 x = 2 Therefore, the man drive at the higher speed for 2 hours. 2. Let there are x ball pens which cost $3 each: 3x + 5(27 - x) = 111 3x + 135 - 5x = 111 2x = 24 x = 12 Therefore, there are 12 ball pens which cost $3 each. 3. Let the original price of a pack of chocolate be $x: 16x + 1 = 14(x + 0.5) 16x + 1 = 14x + 7 2x = 6 x = 3 Hence, the original price of a pack of chocolate is $3. 4. Let the number of $320 tickets sold = x: 320x + 160(2x) + 220(2x + 120) = 132240 320x + 320x + 440x + 26400 = 132240 1080x = 105840 x = 98 i.e. The number of $160, $220 and $320 tickets sold are (98*2), (98*2 + 120), 98 respectively, i.e. 196, 316, 98 respectively.
其他解答:
中一數學練習 ...(快!!4題)
發問:
1.) A man drove his car at 55km/h and increased his speed to 60km.h. He drove 340 km in 6 hours. How long did he drive at the higher speed?2.) The cost of 27 ball pens is &111. Among them, some cost $5 each and the remaining cost $3 each. What is the number of ball pens which cost $3 each?3.) The price of a... 顯示更多 1.) A man drove his car at 55km/h and increased his speed to 60km.h. He drove 340 km in 6 hours. How long did he drive at the higher speed? 2.) The cost of 27 ball pens is &111. Among them, some cost $5 each and the remaining cost $3 each. What is the number of ball pens which cost $3 each? 3.) The price of a pack of chocolates increases by $0.5. Now it costs $1 more to buy 14 packs of chocolates thean to buy 16 packs of chocolates before the increases. Find the original price of a pack of chocolates? 4.) There are 3 types of band show tickets: $160,$220 and $30. The number of $220 tickets sold is 120 more than that of $160 tickets. The number of $160 tickets sold is 2 times that of $320 tickets. If the total income from the tickets is $132240. Find the number of each type of tickets sold? 更新: 列式+過程+答案
最佳解答:
1. Let the man drove his car at the higher speed i.e. 60km/h for x hours: 55(6 - x) + 60x = 340 330 - 55x + 60x = 340 5x = 10 x = 2 Therefore, the man drive at the higher speed for 2 hours. 2. Let there are x ball pens which cost $3 each: 3x + 5(27 - x) = 111 3x + 135 - 5x = 111 2x = 24 x = 12 Therefore, there are 12 ball pens which cost $3 each. 3. Let the original price of a pack of chocolate be $x: 16x + 1 = 14(x + 0.5) 16x + 1 = 14x + 7 2x = 6 x = 3 Hence, the original price of a pack of chocolate is $3. 4. Let the number of $320 tickets sold = x: 320x + 160(2x) + 220(2x + 120) = 132240 320x + 320x + 440x + 26400 = 132240 1080x = 105840 x = 98 i.e. The number of $160, $220 and $320 tickets sold are (98*2), (98*2 + 120), 98 respectively, i.e. 196, 316, 98 respectively.
其他解答:
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