標題:
數學問題(相容數字法,多項式)
發問:
1. 利用相容數字法，估算以下算式: a) 332+317+289+310+294 b) 求上述估算的百分誤差(答案準確至1位小數) 2. 寫出兩個不同的多項式，它們有相同的項數及次數，但相加後，次數會降低。 多項式1: 多項式2: 結果: 更新: 要有步驟的
最佳解答:
1. ( 唔係好sure ) a) 332+317+289+310+294 ~ 330 + 320 + 290 + 310 + 290 ~ 1540 b) 1540/( 332+317+289+310+294 ) = 0.9987 percentage error : 1 - 0.9987 ~ 0.1% ( to 0.1 d. p.) 2. polynomial means sum of x^i for x being variable e.g. 2 x + 1, x^2 , x^2000 - x^3432 項數 number of term, you have to count how many term there is, in our examples , there are 2, 1, 2 terms 2x is a term, +1 is a term (constant term), x^ 2 is a term. but 4*x^3 + 3*x - x^3 has only two terms, 3*x and 3*x^3 次數 is the order of polynomial, it is the most important indicator. examples: 4, 9 , 30000 both has degree of 0. r +10, 4989845948*s - 437435435 both have degree of 1 t^2 + 5t -3 has degree of 2 it is easy to construct two polynomial satisfying your condition. you know coefficient 系數? it means how many of a term, say, in 4k^3 + 2k^2 - 9k -2 the coef for k^3 is 4, coef for k^2 is +2, coef for k is [[ -9 ]] , constant term is -2 just make two polynomial with opposite number of highest order term. for example, x^3 -x^2+x+1 and -x^3 -x^2 +x+1. They are both polynomials of degree 3 having 4 terms. After addition, it becomes -2 x^2 + 2 x + 2 , a polynomial of degree 2.
其他解答:
數學問題(相容數字法,多項式)
發問:
1. 利用相容數字法，估算以下算式: a) 332+317+289+310+294 b) 求上述估算的百分誤差(答案準確至1位小數) 2. 寫出兩個不同的多項式，它們有相同的項數及次數，但相加後，次數會降低。 多項式1: 多項式2: 結果: 更新: 要有步驟的
最佳解答:
1. ( 唔係好sure ) a) 332+317+289+310+294 ~ 330 + 320 + 290 + 310 + 290 ~ 1540 b) 1540/( 332+317+289+310+294 ) = 0.9987 percentage error : 1 - 0.9987 ~ 0.1% ( to 0.1 d. p.) 2. polynomial means sum of x^i for x being variable e.g. 2 x + 1, x^2 , x^2000 - x^3432 項數 number of term, you have to count how many term there is, in our examples , there are 2, 1, 2 terms 2x is a term, +1 is a term (constant term), x^ 2 is a term. but 4*x^3 + 3*x - x^3 has only two terms, 3*x and 3*x^3 次數 is the order of polynomial, it is the most important indicator. examples: 4, 9 , 30000 both has degree of 0. r +10, 4989845948*s - 437435435 both have degree of 1 t^2 + 5t -3 has degree of 2 it is easy to construct two polynomial satisfying your condition. you know coefficient 系數? it means how many of a term, say, in 4k^3 + 2k^2 - 9k -2 the coef for k^3 is 4, coef for k^2 is +2, coef for k is [[ -9 ]] , constant term is -2 just make two polynomial with opposite number of highest order term. for example, x^3 -x^2+x+1 and -x^3 -x^2 +x+1. They are both polynomials of degree 3 having 4 terms. After addition, it becomes -2 x^2 + 2 x + 2 , a polynomial of degree 2.
其他解答:
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1a.1542 b. 0.1 % What is 多項式?4E350C6F8B48ECA2
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