想因式分解x^4+x^2-2x－utefdxd的部落格

標題:

想因式分解x^4+x^2-2x

發問:

e一條數佢分a、b part a.x^4-x b.x^4+x^2-2x a.x(x-1)(x^2+x+1) 但係佢之後話由此︿因式分解x^4+x^2-2x，我就唔識喇，請高手出手相助!!!!!!!!!!

最佳解答:

from a, x(x-1)(x^2+x+1) x^4+x^2-2x =x^4-x+x^2-x from a, x^4-x=x(x-1)(x^2+x+1) therefore, =x(x-1)(x^2+x+1)+x^2-x =x(x-1)(x^2+x+1)+x(x-1) =x(x-1)((x^2+x+1)+1) =x(x-1)(x^2+x+2)

其他解答:

自己計的..我唔知啱唔啱..但我諗係咁計,, x^4 + x^2 - 2x = x [x^3 + (x - 2)] = x [x^3 - (2 - x)] = x [x - (2 - x)] [x^2 + x + (2 - x)] = x (x - 2 + x) (x^2 + x + 2 - x) = x (2x - 2) (x^2 + 2) = 2x (x - 1) (x^2 + 2) 唔知啱唔啱呢...